Solution for VLSM Exercise

1 Specify the eight subnets of 140.25.0.0/16: 

Base Network: 10001100.00011001 .00000000.00000000 = 140.25.0.0/16

Subnet #0: 10001100.00011001. 000 00000.00000000 = 140.25.0.0/19

Subnet #1: 10001100.00011001. 001 00000.00000000 = 140.25.32.0/19

Subnet #2: 10001100.00011001. 010 00000.00000000 = 140.25.64.0/19

Subnet #3: 10001100.00011001. 011 00000.00000000 = 140.25.96.0/19

Subnet #4: 10001100.00011001. 100 00000.00000000 = 140.25.128.0/19

Subnet #5: 10001100.00011001. 101 00000.00000000 = 140.25.160.0/19

Subnet #6: 10001100.00011001. 110 00000.00000000 = 140.25.192.0/19

Subnet #7: 10001100.00011001. 111 00000.00000000 = 140.25.224.0/19 

2 List the host addresses that can be assigned to Subnet #3

(140.25.96.0):

Subnet #3: 10001100.00011001.011 00000.00000000 = 140.25.96.0/19

Host #1: 10001100.00011001.011 00000.00000001 = 140.25.96.1/19

Host #2: 10001100.00011001.011 00000.00000010 = 140.25.96.2/19

Host #3: 10001100.00011001.011 00000.00000011 = 140.25.96.3/19

.

.

Host #8189: 10001100.00011001.011 11111.11111101 = 140.25.127.253/19

Host #8190: 10001100.00011001.011 11111.11111110 = 140.25.127.254/19

3 Identify the broadcast address for Subnet #3 (140.25.96.0):

10001100.00011001.011 11111.11111111 = 140.25.127.255 

4 Specify the 16 subnets of Subnet #6 (140.25.192.0/19):

Subnet #6: 10001100.00011001.110 00000.00000000 = 140.25.192.0/19

Subnet #6 0: 10001100.00011001.110 00000.00000000 = 140.25.192.0/23

Subnet #6 1: 10001100.00011001.110 00010.00000000 = 140.25.194.0/23

Subnet #6 2: 10001100.00011001.110 00100.00000000 = 140.25.196.0/23

Subnet #6 3: 10001100.00011001.110 00110.00000000 = 140.25.198.0/23

Subnet #6 4: 10001100.00011001.110 01000.00000000 = 140.25.200.0/23

.

.

Subnet #6 14: 10001100.00011001.110 11100.00000000 = 140.25.220.0/23

Subnet #6 15: 10001100.00011001.110 11110.00000000 = 140.25.222.0/23 

U N D E R S TA N D I N G   I P   A D D R E S S I N G

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