CLASSES
Examples of Field Declarations
8.3.3
sample.printBoth();
System.out.println(sample.x + " " +
((Point)sample).x);
}
}
then the field
x
 of class
Point
 is no longer hidden within class
Test
. Within
instance methods in the declaration of class
Test
, the simple name
x
 now refers to
the field declared within class
Point
. Code in class
Test
 may still refer to that
same field as
super.x
. The expression
sample.x
 still refers to the field
x
 within
type
Test
, but that field is now an inherited field, and so refers to the field
x
declared in class
Point
. The output from this variant program is:
2 2
2 2
8.3.3.3
Example: Multiply Inherited Fields
A class may inherit two or more fields with the same name, either from two inter 
faces or from its superclass and an interface. A compile time error occurs on any
attempt to refer to any ambiguously inherited field by its simple name. A qualified
name or a field access expression that contains the keyword
super
 ( 15.10.2) may
be used to access such fields unambiguously. In the example:
interface Frob { float v = 2.0f; }
class SuperTest { int v = 3; }
class Test extends SuperTest implements Frob {
public static void main(String[] args) {
new Test().printV();
}
void printV() { System.out.println(v); }
}
the class
Test
 inherits two fields named
v
, one from its superclass
SuperTest
 and
one from its superinterface
Frob
. This in itself is permitted, but a compile time
error occurs because of the use of the simple name
v
 in method
printV
: it cannot
be determined which
v
 is intended.
The following variation uses the field access expression
super.v
 to refer to
the field named
v
 declared in class
SuperTest
 and uses the qualified name
Frob.v
 to refer to the field named
v
 declared in interface
Frob
:
interface Frob { float v = 2.0f; }
class SuperTest { int v = 3; }
class Test extends SuperTest implements Frob {
public static void main(String[] args) {
new Test().printV();
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